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(b)Diborane, Bâ‚‚H6, can be prepared by the following reaction:
NaBH4 (s) + BF3(g) Bâ‚‚Hs(g) + NaBF4(s)

i. Balance the equation

ii. How many moles of NaBH, react with 1.299 mol of BF3?

iii.How many moles of Bâ‚‚H, can be obtained from 0.893 mol of NaBHâ‚‚?

iv. If 1.987 mol of Bâ‚‚H, is obtained, how many moles of NaBF, are produced?
[7 marks]
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