Alex laughed a ball into air the height of the ball can be represented by the equation h=-8t +40t+5, where h is the height in units,and t is the time ,in seconds,after the ball was launched. Graph the equation frim t=0 to t=5 seconds.
For this case the correct equation should be: Â h = -8t ^ 2 + 40t + 5 Â We observe that we have a parabola. Â The direction of the parabola is opening downwards. This is because the coefficient of the quadratic term is negative. Â We must graph the function in the following domain: Â [0, 5] Â Answer: Â see attached image
