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  • 03-03-2016
  • Mathematics
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B^2-4b+4=0
Quadratic formula

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  • 03-03-2016
[tex]b^2-4b+4=0 \\ \\ b = \frac{-(-4) \pm \sqrt{(-4)^2 - 4(1)(4)} }{2(1)} \\ \\ b = \frac{-(-4)}{2(1)} \\ \\ b = 2 \\ \\ [/tex]

The final result is: b = 2.
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