If you plug in the x and y values for the points (X,Y). Then you are able to solve for the equation by seeing whether or not it equals the Y value. Ex. Solving 9a. Step One Equation and Point (2,0) or (X,Y) [tex]y = ({x})^{2} - 3(x) + 2[/tex] Step 2 Plug in and solve [tex]0 = {2}^{2} - 3(2) + 2[/tex] 0=4-6+2
