A lifeguard is in a look out chair and sees a person in distress. The eye level of the lifeguard is 15 feet above the ground. The angle of depression to the person is 34Ëš. What is the horizontal distance between the lifeguard and the person? Round to the nearest foot, and enter the number only.

Respuesta :

Answer:

Horizontal distance between lifeguard and the person is 22 feet.

Step-by-step explanation:

Given: A lifeguard sees a person in distress.The eye level of the lifeguard is 15 feet above the ground. Angle of depression is 34°.

To find: Horizontal distance between lifeguard and the person.

Solution : If we draw a triangle then tan∅ = [tex]\frac{height}{base}[/tex]

               Here base is the horizontal distance.

               Now we put the values in the formula.

               tan 34° = [tex]\frac{15}{base}[/tex]

              Or Base = [tex]\frac{15}{tan34}[/tex]

                             = [tex]\frac{15}{0.675} = 22.22 feet[/tex]

So the answer is 22 feet.