Answer:
Q6. a₁₁ = 236 196; S₁₁ = 354 292
Q7. 354 292
Q8. a) Converges, S = 320/3; b) diverges
Step-by-step explanation:
6. Geometric sequence
The first three terms of your sequence are 4, 12, 36.
Each term differs from the previous one by a factor of 3, so it is a geometric sequence.
Each term has the form
aₙ = a₁rⁿ⁻¹
In your sequence, a₁ = 4 and r = 3.
Thus, the formula for the nth term is
aₙ = 4(3)ⁿ⁻¹
The 11th term is
a₁₁ = 4(3)¹¹⁻¹ = 4(3)¹⁰ = 4 × 59 049 = 236 196
The formula for the sum of the first n terms of a geometric series is
Sum = a₁[(1 - rⁿ)/(1 - r)]
For the sum over the first 11 terms,
Sum = 4[(1 - 3¹¹)/(1 - 3)
= 4(1 - 177 147)/(-2)
= -2(-177 146)
= 354 292
7. Bouncing ball
Mathematically, the ball never stops bouncing. The height of each bounce just gets infinitesimally small.
So , you have an infinite geometric series in which the first term is 40 ft and each successive term is 90 % of the previous term.
The general formula for the nth term is
aₙ = a₁rⁿ⁻¹
with a₁ = 40 ft and r = 0.90.
Since |r| <1, we have a convergent series, and the formula for the sum is
S = a₁/(1-r)
∴ S = 40/(1 - 0.90) = 40/0.10 = 400 ft
The bouncing ball will have travelled 400 ft.
8. Test for convergence
a) 80 + 20 + 5 + 5/4 + ...
r = a₂/a₁ = 20/80 = ¼
r < 1, so the series converges.
S = 80/( 1 - ¼) = 80/¾ = 80 × ⁴/₃ = 320/3
The sum of the series is 320/3.
b) 2/9 + 4/3 + 8 + ...
r = a₂/a₁ = (⁴/₃)/(²/₉) = ⁴/₃ × ⁹/₂ = 2 × 3 = 6.
r > 1, so the series diverges.
6 Answer: 236,196 and 354,294
Step-by-step explanation:
[tex]\text{Find the 11th term:}\\a_1=4\qquad r=\dfrac{12}{4}=3\qquad n=11\\\\a_n=a_1\cdot r^{n-1}\\a_{11}=4\cdot (3)^{11-1}\\.\quad =4\cdot3^{10}\\.\quad =4\cdot 59,049\\.\quad =\large\boxed{236,196}\\\\\\\text{Find the sum:}\\S_n=\dfrac{a_1(1-r^n)}{1-r}\\\\\\S_{11}=\dfrac{4(1-3^{11})}{1-3}\\\\\\.\quad =\dfrac{4(1-177,147)}{-2}\\\\.\quad =-2(-177,146)\\\\.\quad =\large\boxed{354,294}[/tex]
7 Answer: 400
Step-by-step explanation:
[tex]\sum\limits^{n=1}_\infty 40(0.9)^{n-1}\\\\a_1=40\qquad r=0.9\\\\S_\infty =\dfrac{a_1}{1-r}\\\\\\.\quad =\dfrac{40}{1-0.9}\\\\\\.\quad =\dfrac{40}{0.1}\\\\\\.\quad =\large\boxed{400}[/tex]
8 Answer: a) converges
b) diverges
Step-by-step explanation:
A series converges if: -1 < r < 1
a) 80 + 20 + 5 + [tex]\frac{5}{4}[/tex]
[tex]a)\ r=\dfrac{a_2}{a_1}=\dfrac{20}{80}=\dfrac{1}{4}\implies \text{converges}\\\\\\b)\ r={a_2}\div{a_1}=\dfrac{4}{3}\div \dfrac{2}{9}=\dfrac{4}{3}\times \dfrac{9}{2}=2\times 3=6\implies \text{diverges}[/tex]
