Answer:
20.62 N
4.123 m/s^2
Explanation:
A = 20 N west
B = 5 N North
m = 5 kg
Both the forces acting at right angle
Use the formula of resultant of two vectors.
Let r be the magnitude of resultant of two vectors.
[tex]R = \sqrt{A^{2} + B^{2} + 2 A B Cos\theta}[/tex]
[tex]R = \sqrt{20^{2} + 5^{2} + 2 \times 20 \times 5 \times Cos90}[/tex]
R = 20.62 N
Let a be the acceleeration.
a = Net force / mass = R / m = 20.62 / 5
a = 4.123 m/s^2
