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Accomplished silver workers in India can pound silver into incredibly thin sheets, as thin as 2.87 × 10-7 m. Find the area of such a sheet that can be formed from 1.00 kg of silver. [silver density = 10500 kg/m3]

Respuesta :

Answer:

A=331.84 m2

Step-by-step explanation:

Hello

The density of a object is defined by

[tex]d=\frac{m}{v}[/tex]

d is the density

m is the mass of the object

v es the volume of the object

We  have

[tex]thickness= t =2.87 * 10^{-7} m\\\ A=unknown=area\\ Volume=Area*thickness\\m=1 kg \\\\\\d=10500kg/m^{3}[/tex]

[tex]d=\frac{m}{v}\\ v=\frac{m}{d}\\ A*t=\frac{m}{d}\\ A=\frac{m}{d*t}\\ \\A=\frac{1 kg}{10500\frac{kg}{m^{3} }*2.87*10^{-7}m}\\A=331.84m^{2}[/tex]

I hope it helps

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