Answer:
Magnetic field, B = 0.199 T
Explanation:
It is given that,
Radius of circular loop, r = 11.7 cm = 0.117 m
Magnetic flux through the loop, [tex]\phi=8.6\times 10^{-3}\ T/m^2[/tex]
The magnetic flux linked through the loop is :
[tex]\phi=B.A[/tex]
[tex]\phi=BA\ cos\theta[/tex]
Here, [tex]\theta=0[/tex]
[tex]B=\dfrac{\phi}{A}[/tex]
or
[tex]B=\dfrac{\phi}{\pi r^2}[/tex]
[tex]B=\dfrac{8.6\times 10^{-3}}{\pi (0.117 )^2}[/tex]
B = 0.199 T
So, the strength of the magnetic field is 0.199 T. Hence, this is the required solution.
