Respuesta :

lukyo
Let [tex]x[/tex] be the width of the rectangle. 

Since the perimeter of this rectangle is 100, then the height of the triangle must be [tex]50-x.[/tex]


Both width and height are positive numbers, so we must have

[tex]x>0~~\text{ and }~~50-x>0\\\\ x>0~~\text{ and }~~50>x\\\\ 0<x<50[/tex]

There are infinity real numbers that are greater than zero and less than 50. Therefore, there are infinity rectangles having a perimeter of 100.

[tex]\bullet~~[/tex] width: [tex]x[/tex]
[tex]\bullet~~[/tex] height: [tex]50-x[/tex]

[tex]0<x<50[/tex]

(You can pick any real number between [tex]0[/tex] and [tex]50[/tex] for the [tex]x[/tex] value )

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