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Please help!! I need step by steps!! Thank you

1. There are three consecutive even numbers such that twice the first is 20 more than the second. Find the numbers.

2. 10x - 5-2 (x+7) = 2 (4-x) + 10x

3. -4x + 5 - 1 (x-4) = 5x + 5 + 4 (1 - 3x)

4. 8 - (9x+6) = 5x + 5 + 4 (1 - 3x)

Respuesta :

Answer:

Part 1) The numbers are 22,24 and 26

Part 2) The value of x has no solution

Part 3) The value of x has no solution

Part 4) The value of x is [tex]x=-3.5[/tex]

Step-by-step explanation:

Part 1)

Let

x ----> the first even number

x+2 ---> the second consecutive even number

x+4 ---> the third consecutive even number

we know that

[tex]2(x)=(x+2)+20[/tex]

Solve for x

[tex]2x=x+22[/tex]

[tex]2x-x=22[/tex]

[tex]x=22[/tex]

therefore

The numbers are 22,24 and 26

Part 2) we have

[tex]10x-5-2(x+7)=2(4-x)+10x[/tex]

Distribute in the left and the right side to remove the parenthesis

[tex]10x-5-2x-14=8-2x+10x[/tex]

Combine like terms

[tex]8x-19=8x+8[/tex]

[tex]-19=8[/tex] -----> is not true

therefore

The value of x has no solution

Part 3) we have

[tex]-4x+5-1(x-4)=5x+5+4(1-3x)[/tex]

Distribute in the left and the right side to remove the parenthesis

[tex]-4x+5-x+4=5x+5+4-12x[/tex]

Combine like terms

[tex]-5x+9=-7x+9[/tex]

[tex]-5x=-7x[/tex] -----> is not true

therefore

The value of x has no solution

Part 3) we have

[tex]8-(9x+6)=5x+5+4(1-3x)[/tex]

Distribute in the right side to remove the parenthesis

[tex]8-9x-6=5x+5+4-12x[/tex]

Combine like terms

[tex]2-9x=-7x+9[/tex]

[tex]9x-7x=2-9[/tex]

[tex]2x=-7[/tex]

[tex]x=-3.5[/tex]