cos 0ΒΊ=1 Β Β Β Β Β Β Β Β Β Β Β Β Β Β sin 0ΒΊ=0
cos 45ΒΊ=β2 / 2 Β Β Β Β Β Β Β Β Β sin 45ΒΊ=β2 / 2
cos 90ΒΊ=0 Β Β Β Β Β Β Β Β Β Β Β Β sin 90ΒΊ=1
Therefore, if cos (A)< sin (A), then A>45ΒΊ.
Answer: Given that cos (A)<sin(A), the angle measures for Angle A that would make a true this statement will be:Β
65 degrees
70 degrees
85 degrees.Β