Respuesta :
Answer:
molar volume of vapor ethanol is [tex]V = 1.043 \times 10^{-3} m^3/mol[/tex]
mass of ethanol is 15430.22 g
Explanation:
By using ideal gas equation
PV = nRT
Where P is pressure , R is gas constant
so, volume is
[tex]V = \frac{RT}{P} = \frac{8.314\times (480+273)}{6000\times 10^3}[/tex]
[tex]V = 1.043 \times 10^{-3} m^3/mol[/tex]
molar volume of vapor ethanol is
[tex]V = 1.043 \times 10^{-3} m^3/mol[/tex]
b)
volume of vessel is given [tex]0.35 m^3[/tex]
therefore total moles of ethanol in given vessel will be
[tex]n =\frac{V_{vessel}}{V}[/tex]
[tex]n =\frac{0.35}{1.043\times10^{-3}}[/tex]
n = 335.44 mol
we know that
mole is given as [/tex]n = \frac{mass}{moleculae weight}[/tex]
weight of ethanol is 46 g/mol
n\times 46 = mass
[tex]335.44\times 46 = 15430.22 g[/tex]
mass of ethanol is 15430.22 g
