Answer:
The period is 0.628s
Explanation:
As the system mass-spring is in simple harmonic motion, the period is given by the equation:
[tex]T=2\pi \sqrt{\frac{m}{k}}[/tex]
where m is the mass of 2kg and k is the spring constant [tex]200\frac{N}{m}[/tex]
Replacing the values in the equation, we have:
[tex]T=2\pi \sqrt{\frac{2Kg}{200\frac{N}{m}}}[/tex]
And finally we find the value of the period, that is:
[tex]T=0.628s[/tex]
