Answer:
84.44N
Explanation:
Hi!
The force F between two charges qā and qā at a distance r from each other is given by Coulomb's law:
[tex]F = k_c \frac{q_1 q_2}{r^2}[/tex]
The force on the negative charge qā is the sum of the forces from the other two charges. This forces have equal magnitude as both distances are 48cm. The magnitud is:
[tex]F_{1,2} =F_{1,3} = -k_c\frac{(26\mu C)^2}{(48cm)^2}=-9*10^9Nm^2C^{-2}*0.54*\frac{10^{-12}C^2}{10^{-4}m^2}=-48.75N\\[/tex]
(negative means attractive)
The sum of the forces, because of symmetry reasons actos along line L (see the figure), and its magnitud is:
[tex]F = 2*48.75*\cos(30\Āŗ)N = 84.44N[/tex]
