Answer: 21
Step-by-step explanation:
Given : A bag containing five red marbles, two green ones, one transparent one, four yellow ones, and two orange ones .
Total marbles other than red or green = 1+4+2=7
Now, the number of combinations to select five marbles from the set of 7 will be :-
[tex]7C_5=\dfrac{7!}{5!(7-5)!}=\dfrac{7\times6\times5!}{5!\times2!}=21[/tex]
Hence, the number of possible sets of five marbles are there in which none of them are red or green =21
