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Two cars drive on a straight highway. At time t=0, car 1 passes mile marker 0 traveling due east with a speed of 20.0 m/s . At the same time, car 2 is 0.80 km east of mile marker 0 traveling at 26.0 m/s due west. Car 1 is speeding up with an acceleration of magnitude 0.40 m/s^2 , and car 2 is slowing down with an acceleration of magnitude 0.80 m/s^2 . a.) Write x-versus-t equations of motion for both cars, taking east as the positive direction.
b.) At what time do the cars pass next to one another?

Respuesta :

Answer:

Explanation:

a ) Equation for car 1

X = 20 t + 1/2 x 0.40 t² ( initial velocity is 20 and acceleration is 0.4 )

Equation for car 2

X = 800 - ( 26 t - 1/2 x0.80 t² ) [ when t = 0 , X = 800 m and  with time t , X decreases ]

b ) Let after time t  they  meet , then X will be equal for both of them at t.

20 t + 1/2 x 0.40 t² = 800 - ( 26 t - 1/2 x0.80 t² )

0.20 t²- 46 t +800 = 0

t = 19 s and 211 s .

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