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A chemist prepares a solution of nickel(II) chloride (NiCly) by measuring out 61.3 umol of nickel(II) chloride into a 200 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in umol/L of the chemist's nickel(II) chloride solution. Round your answer to 3 significant digits. x 5 ? Explanation Check 2009 Mew Econ Aires Reserved. Terms of Use

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Answer:

The concentration of nickel(II) chloride in μmol/l will be 307 μmol/l

Explanation:

If in 200 ml you have 61.3 μmol, then, in 1000 ml ( 1 l) you will have:

1000 ml * (61.3 μmol / 200 ml) = 306.5 μmol.

Rounded to 3 significant digits: 307 μmol.

The concentration will be 307 μmol/l or 307 μM.

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