Light in vacuum is incident on the surface of a slab of transparent material. In the vacuum the beam makes an angle of 39.9° with the normal to the surface, while in the slab it makes an angle of 18.2° with the normal. What is the index of refraction of the transparent material?

Respuesta :

Answer:

n=2.053

Explanation:

We will use Snell's Law defined as:

[tex]n_{1}*Sin\theta_{1}=n_{2}*Sin\theta_{2}[/tex]

Where n values are indexes of refraction and [tex]\theta[/tex] values are the angles in each medium. For vacuum, the index of refraction in n=1. With this we have enough information to state:

[tex]1*Sin(39.9)=n_{2}*Sin(18.2)[/tex]

Solving for [tex]n_{2}[/tex] yields:

[tex]n_{2}=\frac{Sin(39.9)}{Sin(18.2)}=2.053[/tex]

Remember to use degrees for trigonometric functions instead of radians!