Respuesta :
Explanation:
According to Buoyance equation,
     m = [tex][m' \times \frac{1 - \frac{d_{a}}{d_{w}}}{1 - \frac{d_{a}}{d}}][/tex]
where, Â Â Â m = true mass
         m' = mass read from the balance = 17.320 g
       [tex]d_{a}[/tex] = density of air = 0.0012 g/ml
       [tex]d_{w}[/tex] = density of the balance = 7.5 g/ml
          d = density of liquid octane = 0.7025 g/ml
Now, putting all the given values into the above formula and calculate the true mass as follows.
   m = [tex][m' \times \frac{1 - \frac{d_{a}}{d_{w}}}{1 - \frac{d_{a}}{d}}][/tex]  Â
     = [tex][17.320 g \times \frac{1 - \frac{0.0012 g/ml}{7.5 g/ml}}{1 - \frac{0.0012 g/ml}{0.7025}}][/tex]
     = [tex]17.320 g \times 0.999850[/tex]        Â
     = 17.317 g
Thus, we can conclude that the true mass of octane is 17.317 g.
