For the given conditions, we won’t get a practical solution.
Solution:
Given, An automobile dealer had 288 cars and trucks in stock during the month. Â
He must pay an inventory fee of 52 per car and $5 per truck. Â
He paid $849 for inventory foes. Â
We have to find how many cars and Trucks did he have during the month?
Now, let the number of trucks be n, then number of cars will be 288 – n
And, according to given information,
[tex]\begin{array}{l}{5 \times n+52 \times(288-n)=849} \\\\ {\rightarrow 5 n+52 \times 288-52 n=849} \\\\ {\rightarrow 52 n-5 n=14976-849} \\\\ {\rightarrow 47 n=14127} \\\\ {\rightarrow n=300.57}\end{array}[/tex]
Here we got n > number of cars and trucks, which is practically impossible. Â
Hence, for the given conditions, we won’t get a practical solution