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Suppose we are given a square coil that is 5.5 cm on a side containing 100 loops of very fine wire. The total resistance of this coil is 1.7 ✕ 10−3 Ω. This coil is initially centered on the origin with its sides parallel to the x- and y-axes. It is being rotated about the y-axis in a uniform magnetic field of 1.3 T along the z-axis, with an angular velocity of 2.0 rad/sec. Find the magnitude of the peak value of the induced current flowing in this coil under these conditions.

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Answer:

I = 578A

Explanation:

The magnitude of the peak value of the induced current flowing in a coild is given by

[tex]I = \frac{\epsilon_{max}}{R}[/tex]

[tex]I = \frac{NBA\omega}{R}[/tex]

Where

I= current

N = Number of loops

[tex]\omega =[/tex] angular velocity

R= Resistance

B = Magnetic field

A = Area

Replacing our values we have that,

[tex]I = \frac{(100)(1.3)(0.055)^2(2.5)}{1.7*10^{-3}}[/tex]

[tex]I = 578A[/tex]

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