tegan21
contestada

Find the ninth term of the
geometric sequence, given the
first term and common ratio.
a1=1 and r=-1/3

Respuesta :

devishri1977

Answer:

Step-by-step explanation:

n th term = a ( r^(n-1) - 1)/ (r-1)

Ninth term = 1 * [ (-1/3)⁸ - 1 ] / (-1/3 -1)

= (1/6561) -1 / ( -1 -3/3) = [(1 - 6561) / 6561]  / [-4/3]

= [-6560/6561]  / -4/3

= -6560 * 3 / 6561 * -4

=  1640 / 2187

Answer:

1(-1/3)^8

Answer: 1/6561

Step-by-step explanation: