Answer:
F = -307.4 N
Explanation:
It is given that,
Mass of the baseball, m = 0.145 kg
Initial speed of the baseball, u = 60 m/s
Final speed of the baseball, [tex]v=65\ cos(30)=56.29\ m/s[/tex]
Time of contact, [tex]t=1.75\ ms=1.75\times 10^{-3}\ s[/tex]
(a) It is assumed to find the horizontal component of average force. It is given by :
[tex]F=m\dfrac{v-u}{t}[/tex]
[tex]F=0.145\dfrac{56.29-60}{1.75\times 10^{-3}}[/tex]
F = -307.4 N
So, the horizontal component of average force is 307.4 N. Hence, this is the required solution.
