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sam jimmy and andre shared a number of pennies in the ratio 8:5:3. same and andre recieved a total of 671 pennies. how many more pennies did jimmy recieve than andre. pls helppp​

Respuesta :

frika

Answer:

122

Step-by-step explanation:

Sam,Jimmy and Andre shared a number of pennies in the ratio 8:5:3. Then

Sam has = 8x pennies

Jimmy has = 5x pennies

Andre has = 3x pennies.

Sam and Andre recieved a total of 671 pennies, so

[tex]8x+3x=671\\ \\11x=671\\ \\x=61[/tex]

Hence,

Sam has [tex]=8\cdot 61=488[/tex] pennies

Jimmy has [tex]=5\cdot 61=305[/tex] pennies

Andre has [tex]=3\cdot 61=183[/tex] pennies.

Jimmi recieved [tex]305-183=122[/tex] more pennies than Andre.

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