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The point slope form of the equation of the line that passes through (-9, -2) and (1, 3) is
slope-intercept form of the equation for this line?
o y = 2 x + 2
0 y = 2 x 4
o y = x + 2
O y = x - 2
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Answer:

The slope intercept  of the given line equation AB is [tex]y  = \frac{1}{2}  ( x)- \frac{5}{2}[/tex]

Step-by-step explanation:

Here,the two given point s are A ( -9,-2) and B (1,3).

Now, the slope m of the line AB  =  [tex]= \frac{y_2 - y_1}{x_2 -x_1}[/tex]

[tex]\implies m = \frac{3 - (-2)}{1 - (-9)}  = \frac{3+2}{1+9}  = \frac{5}{10}  = \frac{1}{2}[/tex]

or, the slope of line AB = 1/2

Now, the POINT SLOPE FORM of any equation with point (x0,y0) and slope m is given as :

y - y0 = m (x -x0)

So, the line equation of AB is given as :

[tex]y - 3 = \frac{1}{2}  ( x-1)\\\implies y  =3 +  \frac{1}{2}  ( x-1)\\or, y  = \frac{1}{2}  ( x)- \frac{5}{2}[/tex]

SLOPE INTERCEPT form is y = mx + c

Hence, the slope intercept  of the given line equation AB is [tex]y  = \frac{1}{2}  ( x)- \frac{5}{2}[/tex]

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