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`A chemical known as pyrite is sometimes called Fool's Gold because of it's shiny color. However, it has no gold atoms in it at all! In fact, it's just iron and sulfur atoms at a molar ratio of 1 mole of iron to 2 moles of sulfur. So, using this to determine its chemical formula, what, then, is the %Fe (by mass) in Fool's Gold?

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dsdrajlin

Answer:

46.55%

Explanation:

The molar ratio is 1 mole of iron to 2 moles of sulfur, which means that the empirical formula is FeSâ‚‚.

The mass of Fe in 1 mole of FeSâ‚‚ is 55.85 g.

The mass of S in 1 mole of FeS₂ is 2 × 32.07 g = 64.14 g.

The mass of 1 mole of FeSâ‚‚ is 55.85 g + 64.14 g = 119.99 g.

The mass percent of Fe in FeSâ‚‚ is:

[tex]\frac{55.85g}{119.99g} .100\% = 46.55\%[/tex]

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