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Suppose that there are two types of tickets to show advance and same day the combine cost of one advanced ticket and one same day ticket to $70 for one performance 30 advance tickets and 25 same day tickets were sold the total amount paid for the tickets was $1950. what was the price of each kind of ticket

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texaschic101

Answer:

Step-by-step explanation:

x = advance and y = same day

x + y = 70.......x = 70 - y

30x + 25y = 1950

30(70 - y) + 25y = 1950

2100 - 30y + 25y = 1950

-5y = 1950 - 2100

-5y = - 150

y = -150/-5

y = 30 <===== there were 30 same day tickets

x + y = 70

x + 30 = 70

x = 70 - 30

x = 40 <==== there were 40 advance tickets

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