Answer:
200.00 mol    Â
Explanation:
Given data:
Moles of nitric acid produced = ?
Moles of nitrogen dioxide = 300.00 mol
Solution:
Chemical equation:
3NO₂ + H₂O  →  2HNO₃ + NO
Now we will compare the moles of nirtic acid with nitrogen dioxide.
        NO₂       :        HNO₃
          3        :          2
        300.00    :         2/3×300 = 199.99 mol
Nearest to 0.01:
200.00 mol    Â