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If L is the line through the point P=(3,2,1) and parallel to the vector v=⟨2,1,−3⟩, what is an equation of the plane that contains L and the point Q=(−2,3,1)?

Respuesta :

sqdancefan

Answer:

  3x +15y +7z = 46

Step-by-step explanation:

The cross product of v = <2, 1, -3> and PQ = <-5, 1, 0> is <3, 15, 7>, the normal vector of the plane of interest. That plane contains P and Q, so the constant in the plane's equation will be ...

  <3, 15, 7> · <3, 2, 1> = 46

The desired equation is ...

  3x +15y +7z = 46

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