Answer:
[tex][ln \frac{x(x^2 + 1)}{(x + 1)}]^\frac{3}{2}[/tex]
Step-by-step explanation:
[tex]\frac{3}{2} [ln x(x^2 + 1) - ln(x + 1)][/tex]
ln(m/n)= lnm - ln(n)
[tex]\frac{3}{2}[ln x(x^2 + 1) - ln(x + 1)][/tex]
[tex]\frac{3}{2}[ln \frac{x(x^2 + 1)}{(x + 1)}][/tex]
3/2 is before ln. so we move the fraction 3/2 to the exponent
as per log property we move the fraction to the exponent
[tex][ln \frac{x(x^2 + 1)}{(x + 1)}]^\frac{3}{2}[/tex]
