Respuesta :

Step-by-step explanation:

[tex]a(b+c-bc)-b(c+a-ac)+c(b-a)[/tex]

Distribute over the parenthesis:

[tex](ab+ac-abc)+(-bc-ab+abc)+(bc-ac)\\ab+ac-abc-bc-ab+abc+bc-ac[/tex]

Group like terms:

[tex](ab-ab)+(ac-ac)+(abc-abc)+(cb-cb)[/tex]

Anything subtracted from itself is 0.

Simplify:

[tex]0+0+0+0\\0[/tex]