Answer:
a) (g(x), f(u)) = ( 7*√x , e^u )
b)  y ' = 3.5 * e^(7*√x) / √x
Step-by-step explanation:
Given:
- The given function:
                    y = e^(7*√x)
Find:
- Express the given function as a composite of f(g(x)). Where, u = g(x) and y = f(u).
- Express the derivative of y, y'?
Solution:
- We will assume the exponent of  the natural log to be the u. So u is:
                   u = g(x) = 7*√x
- Then y is a function of u as follows:
                   y = f(u) = e^u
- The composite function is as follows:
                  (g(x), f(u)) = ( 7*√x , e^u )
- The derivative of y is such that:
                  y = f(g(x))
                  y' = f' (g(x) ) * g'(x)
                  y' = f'(u) * g'(x)
                  y' = e^u* 3.5 / √x
- Hence,
                  y ' = 3.5 * e^(7*√x) / √x
               Â