Answer:
0.080625 m/s
Explanation:
Horizontally, the total momentum must be conserved, meaning the momentum before and after the throw must be the same.
The total momentum before the throw is 0, and so is after the throw:
mv + MV = 0
where m, M are the masses of the ball and the quarterback, respectively. v and V are the velocities of the ball and the quarterback, respectively.
0.43*15 + 80V = 0
80V = -6.45
V = -6.45 / 80 = -0.080625 m/s
So he will be moving in the opposite direction with the ball at the rate of 0.080625 m/s
