samantha7336 samantha7336

15-03-2020
Mathematics

contestada

Where is the removable discontinuity of f(x) located?
x = -5
F(x)=5x+10/x^2+7x+10

Respuesta :

salatulmaghrib salatulmaghrib

15-03-2020

The discontinuity of f(x) is at x=25. The denominator goes to zero.

Answer Link

Officialalehpeter Officialalehpeter

15-03-2020

Answer:

F(x)=0

Step-by-step explanation:

5x+10/x^2+7x+10

When x=-5

Substitute the value of x in the equation

5(-5)+10/(-5^2+7(-5)+10

-25+10/25-35+10

-15/-10+10

-15/0

=0

Answer Link

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