brainythesmurf
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Write a formula to describe the sequence

1, 0.9, 0.8, 0.7, 0.6, 0.5….

A. A(n) = 1 − A(n − 1)
B. A(n) = n − 0.1(n − 1)
C. A(n) = 1 − 0.1n
D. A(n) = 1 − 0.1(n − 1)

Respuesta :

devishri1977

Answer:

d

Step-by-step explanation:

A(n) = 1 - 0.1(n-1)

A(1) = 1- 0.1*(1-1) = 1 - 0.1*0 = 1

A(2) = 1- 0.1*(2-1) = 1 - 0.1*1 = 1- 0.1 = 0.9

A(3) = 1 - 0.1(3-1) = 1 - 0.1*2 = 1-0.2=0.8

Method:

A(1)=1

D = A(2)-A(1) = 0.9 - 1 = -0.1

A(n) = A(1)+(n-1)*d = 1 + (n-1)*(-0.1)

     = 1 - 0.1(n -1)