An egg falls from a nest at a height of 4m. What speed will it have when it is 1m from the ground? Neglect air resistance and take g as 9.8m/s^2​

Respuesta :

Answer: 7.66 m/s

Explanation:

This situation is related to free fall (vertical motion). Hence, this can be considered a one-dimension problem and we can use the following equation:

[tex]V^{2}=V_{o}^{2}+2gd[/tex]

Where:

[tex]V[/tex] is the final velocity of the egg at the asked height

[tex]V_{o}=0 m/s[/tex] is the initial velocity of the egg

[tex]g=9.8 m/s^{2}[/tex] is the acceleration due gravity

[tex]d=4 m- 1m= 3m[/tex] is the distance at which the egg is from the nest, when it is [tex]1 m[/tex] from the ground

Isolating [tex]V[/tex]:

[tex]V=\sqrt{V_{o}^{2}+2gd}[/tex]

Substituting the known values:

[tex]V=\sqrt{2(9.8 m/s^{2})(3 m)}[/tex]

[tex]V=7.66 m/s[/tex] This is the final velocity of the egg