Answer:
1.364 m
Explanation:
We are given that
Frequency,f=110 MHz=[tex]110\times 10^{6}Hz[/tex]
[tex]1MHz=10^6Hz[/tex]
We have to find the distance between the nodal planes of the magnetic field.
We know that
Wavelength,[tex]\lambda=\frac{c}{f}[/tex]
Where c=[tex]3\times 10^8m/s[/tex]
Using the formula
[tex]\lambda=\frac{3\times 10^8}{110\times 10^6}=2.727 m[/tex]
Distance between nodal planes of the magnetic field
[tex]d=\frac{\lambda}{2}[/tex]
[tex]d=\frac{2.727}{2}=1.364 m[/tex]
