Answer:
B
Explanation:
We are given that
A.Atmospheric pressure=[tex]P_0=1.01\times 10^5N/m^2[/tex]
B.Mass,m=70 kg
Area,A=[tex]50 cm^2=50\times 10^{-4} m^2[/tex]
[tex]1 m^2=10^4 cm^2[/tex]
Force=mg
Where [tex]g=9.8 m/s^2[/tex]
Using the formula
[tex]F=70\times 9.8=686 N[/tex]
[tex]P=\frac{F}{A}=\frac{686}{50\times 10^{-4}}=1.37\times 10^5 N/m^2[/tex]
C.Mass ,m=2.5 kg
Area,A=[tex]22\times 28=616 cm^2=616\times 10^{-4} m^2[/tex]
Pressure=[tex]\frac{mg}{A}=\frac{2.5\times 9.8}{616\times 10^{-4}}=397.7 N/m^2[/tex]
In situation B has greatest pressure.