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Jacy has $1,000 to invest in either a fund that pays approximately 4.6% per year or in a savings account with an annual interest rate of 1.8%. Write a polynomial
function S(x) to represent the interest Jacy will earn in 1 year by investing x dollars in the fund and the remainder in the savings account​

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Answer:

S(x) = 0.046x + 0.018(1000-x)

Step-by-step explanation:

Given that:

  • A fund rate: 4.6% = 0.046
  • Saving account rate:  1.8% = 0.018

Let x is the amount Jacy invest in the fund so (1000-x) is the amount he invests in the  savings account​

So a polynomial  function S(x) to represent the interest Jacy will earn in 1 year is:

S(x) = 0.046x + 0.018(1000-x)

Hope it will find you well.

Answer:

S(x)=18-0.028x

Step-by-step explanation:

Jacy has a total of $1,000 to invest.

  • He invest x dollars in the funds
  • Therefore, amount in the savings account = 1000-x

Interest Rate of the Fund = 4.6% =0.046

Interest Earned on the Fund= Principal X Interest Rate = 0.046x

Interest rate of the Savings Account = 1.8% =0.018

Interest Earned on the Savings Account= 0.018(1000-x) =18-0.018x

Total Interest Earned by Jacy

= Interest Earned on the Fund+Interest Earned on the Savings Account

= 0.046x+ 18-0.018x

=18-0.028x

Therefore, the interest Jacy will earn in 1 year is:

S(x)=18-0.028x

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