Answer:
a) This heat engine is possible since real efficiency is lesser than theoretical efficiency, b) [tex]Q_{H} = 1250\,kJ[/tex], c) [tex]Q_{L} = 750\,kJ[/tex].
Explanation:
a) The maximum theoretical efficiency of a heat efficiency is given by the Carnot's cycle, whose formula is:
[tex]\eta_{max} = \left(1 - \frac{773.15\,K}{1473.15\,K}\right)\times 100\,\%[/tex]
[tex]\eta_{max} = 47.5\,\%[/tex]
This heat engine is possible since real efficiency is lesser than theoretical efficiency.
b) The heat supplied to the engine by the heat source:
[tex]Q_{H} = \frac{W}{\eta_{real}}[/tex]
[tex]Q_{H} = \frac{500\,kJ}{0.4}[/tex]
[tex]Q_{H} = 1250\,kJ[/tex]
c) The heat rejected to heat sink is:
[tex]Q_{L} = Q_{H} - W[/tex]
[tex]Q_{L} = 1250\,kJ - 500\,kJ[/tex]
[tex]Q_{L} = 750\,kJ[/tex]
