Answer:
x=1
Explain:
y=2x^2−4x+1
dy/dx=4x-4
The line of symmetry will be where the curve turns (due to the nature of the
x^2 graph.
This is also when the gradient of the curve is 0.
Therefore, let
dy/dx=0
This forms an equation such that:
4x−4=0
solve for x,
x=1
and line of symmetry falls on the line
x=1
