Answer: 3.56*10^-3 Ω
Explanation:
Given
Speed of bullet, v = 530 m/s
Distance during one RC time constant, d = 1 mm = 1*10^-3 m
Capacitance of the capacitor, C = 530 µF
v = d / t = d / Ï„, so that
Ï„ = d / v
The time constant for the RC circuit is
Ï„ = RC, if we make R subject of formula we have
R = Ï„ / C. Substituting the relation for Ï„
R = d / vC
R = 1*10^-3 / (530 * 530*10^-6)
R = 1*10^-3 / 0.2809
R = 3.56*10^-3 Ω
Therefore, the resistance in the flash tube is 3.56*10^-3 mΩ