Use the graph of f(x) to explain the relationship between the real zeros of f(x) and its intercept(s).
f(x) has one real zero at β2 because the graph of the function has an intercept at (0, β2).
f(x) has two real zeros at β4 and β2 because the graph of the function has intercepts at (β4, 0) and (0, β2).
f(x) has no real zeros because the graph of the function does not pass through (0, 0).
f(x) has one real zero at β4 because the graph of the function has an intercept at (β4, 0).
