Respuesta :
Answer:
a) c, s
b) P(c, s) = 60c + 90s
c) c + s ≤ 320
50c + 100s ≤ 20000
100c + 40s ≤ 19200
d) [tex]c + s+s_1=320[/tex]
[tex]50c + 100s+s_2=20000[/tex]
[tex]100c + 40s+s_3=19200[/tex]
Step-by-step explanation:
a) Let c represent the acres of corn planted and s represent the acres of soybeans planted.
the decision variables of this problem are c and s
a) Each acre of corn yields a profit of $60 and Each acre of soybeans yields a profit of $90
The objective function P(c, s) = 60c + 90s
c)
1) The farmer has a 320 acre farm on which she plants two crops: corn and soya beans. The constraint for this problem is:
c + s ≤ 320
2) Â her expenses are $50 and for each acre of soybeans planted, he expenses are $100. the farmer has only $20,000 on hand. The constraint is:
50c + 100s ≤ 20000
3) Each acre of corn requires 100 bushels of storage and each acre of soybeans requires 40 bushels of storage. Â the total amount of storage space available is 19,200 bushels, The constraint is:
100c + 40s ≤ 19200
d) We have a total of 3 equations. To balance the equations,we would introduce 4 slack variables: [tex]s_1,s_2,s_3[/tex]
[tex]c + s+s_1=320[/tex]
[tex]50c + 100s+s_2=20000[/tex]
[tex]100c + 40s+s_3=19200[/tex]
Therefore solving these equations gives
c=140, s=130
P(c, s) = 60c + 90s = 60(140) + 90(130)= $20100