The height of water shooting from a fountain is modeled by the function f(x) = βˆ’4x2 + 24x βˆ’ 29, where x is the distance from the spout in feet. Complete the square to determine the maximum height of the path of the water. βˆ’4(x βˆ’ 3)2 βˆ’ 29; The maximum height of the water is 3 feet. βˆ’4(x βˆ’ 3)2 βˆ’ 29; The maximum height of the water is 29 feet. βˆ’4(x βˆ’ 3)2 + 7; The maximum height of the water is 7 feet. βˆ’4(x βˆ’ 3)2 + 7; The maximum height of the water is 3 feet.

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Answer:

the maximum height of the water is 7 ft

Step-by-step explanation:

Using " ^ " to indicate exponentiation, we have βˆ’4x^2 + 24x βˆ’ 29.

Rewrite -4x^2 + 24x as -4(x^2 - 6x) and then complete the square of (x^2 - 6x). Β We get:

(x^2 - 6x + 9 - 9), which is exactly equivalent to (x^2 - 6x).

Going back to the original equation: Β βˆ’4x^2 + 24x βˆ’ 29, or

βˆ’4(x^2 - 6x) βˆ’ 29.

Now replace (x^2 - 6x) with (x^2 - 6x + 9 - 9):

-4(x^2 - 6x + 9 - 9) - 29, which simplifies to:

-4(x - 3)^2 + 36 - 29, or

-4(x - 3)^2 + 7, whose vertex is (3, 7). Β Thus, the maximum height of the water is 7 ft. Β 

The path of the water is βˆ’4(x βˆ’ 3)2 + 7 and the maximum height of the water is 7 feet. Then the correct option is C.

What is a quadratic equation?

The quadratic equation is given as axΒ² + bx + c = 0. Then the degree of the equation will be 2.

The height of water shooting from a fountain is modeled by the function given below.

f(x) = βˆ’4xΒ² + 24x βˆ’ 29, where x is the distance from the spout in feet.

Then the quadratic equation is converted into the square form. Then the equation will be

f(x) = βˆ’4xΒ² + 24x βˆ’ 29 - 7 + 7

f(x) = βˆ’4xΒ² + 24x βˆ’ 36 + 7

f(x) = βˆ’4(xΒ² - 6x + 9) + 7

f(x) = βˆ’4(x - 3)Β² + 7

The maximum height of the parabola is 7.

The path of the water is βˆ’4(x βˆ’ 3)2 + 7 and the maximum height of the water is 7 feet.

Then the correct option is C.

More about the quadratic equation link is given below.

https://brainly.com/question/2263981

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