Answer:
From the attached graph, the x-intercept is (13, 0)
Step-by-step explanation:
The question equation is y = x³ + 11·x² - 312·x
To graph the equation, we find the value of y for a given value of x and we plot the values on a graph as follows;
x, Â Â Â Â Â Â Â y
13, Â Â Â Â Â Â 0
14, Â Â Â Â Â Â 532
15, Â Â Â Â Â Â 1170
16, Â Â Â Â Â Â 1920
17, Â Â Â Â Â Â 2788
18, Â Â Â Â Â 3780
19, Â Â Â Â Â 4902
20, Â Â Â Â Â 6160
21, Â Â Â Â Â 7560
22, Â Â Â Â Â 9108
23, Â Â Â Â Â 10810
24, Â Â Â Â Â 12672
25, Â Â Â Â Â 14700
From the graph, the x-intercept can be found at at x = 13.
The x-intercept can also be obtained by equating the right hand side of the equation to 0 (y = 0 is the x -intercept) as follows;
0 = x³ + 11·x² - 312·x
Therefore, x = 0 is one of the x-intercepts
By dividing by x, we have
x² + 11·x - 312 = 0
By completing the square we have
x² + 11·x + (11/2)² = 312+(11/2)²
(x + 11/2)² = 1369/4
x + 11/2 = ±37/2
x = 37/2 - 11/2 = 13 or x = -37/2 - 11/2 = -24
Which gives the x-intercept as (13, 0).