A) The acceleration of the electron along the x -axis is ; 4.57 * 10ā»Ā¹Ā¹ m /s²
B) The speed that would result in the electron experiencing an acceleration Ā along the x-axis is 4.57 * 10ā»Ā¹Ā¹ Ā * time Ā m/s
Given Data :
Electric field ( E ) = ( 2.60i + 5.90j ) V/m
Magnetic field ( B ) = 0.400 k T
Velocity ( v ) = 8.0i m/s
Applying Lorentz force
F = q ( E + ( v * B ) )
Ā = 1.6 * 10ā»Ā¹ā¹ ( 2.60 i Ā + Ā 5.90 j Ā + ( 8.0 i * 0.4 k ) ) N
Ā = 1.6 * 10ā»Ā¹ā¹ ( 2.60 i Ā + Ā 5.90 j + ( 3.2 ( -j ) ) N
Ā = 1.6 * 10ā»Ā¹ā¹ ( Ā 2.60 i Ā + 2.70 j ) N
Ax = 4.57 * 10ā»Ā¹Ā¹ m /s²
Ax = Fx / Mc
Ā Ā = ( 1.6 * 10ā»Ā¹ā¹ * 2.60 ) / 9.1 * 10ā»Ā³Ā¹
Ā Ā = ( 4.16 * 10ā»Ā¹ā¹ ) / 9.1 * 10ā»Ā³Ā¹
  = 0.457 * 10¹²
Ā Ā = 4.57 * 10ā»Ā¹Ā¹ m /s²
Therefore The speed that would result in the electron experiencing an acceleration Ā along the x-axis is 4.57 * 10ā»Ā¹Ā¹ Ā * time
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