Respuesta :
Answer:
L ≈ 1023.0562
Step-by-step explanation:
We are given;
x = t² - 2t
dx/dt = 2t - 2
Also, y = t^(5)
dy/dt = 5t⁴
The arc length formula is;
L = (α,β)∫√[(dx/dt)² + (dy/dt)²]dt
Where α and β are the boundary points. Thus, applying this to our question, we have;
L = (1,4)∫√[(2t - 2)² + (5t⁴)²]dt
L = (1,4)∫√[4t² - 8t + 4 + 25t^(8)]dt
L = (1,4)∫√[25t^(8) + 4t² - 8t + 4]dt
Using online integral calculator, we have;
L ≈ 1023.0562
The length of the curve is 1023.0562 and this can be determined by doing the integration using the calculator.
Given :
- [tex]\rm x = t^2-2t[/tex]
- [tex]\rm y=t^5[/tex]
- [tex]\rm 1\leq t\leq 4[/tex]
First, differentiate x and y with respect to 't'.
[tex]\rm \dfrac{dx}{dt}=2t-2[/tex]
[tex]\rm \dfrac{dy}{dt}=5t^4[/tex]
Now, determine the length of the curve using the below formula:
[tex]\rm L = \int^b_a\sqrt{\left(\dfrac{dx}{dt}\right)^2+\left(\dfrac{dy}{dt}\right)^2} dt[/tex]
Now, substitute the value of the known terms in the above formula and then integrate it.
[tex]\rm L = \int^4_1\sqrt{(2t-2)^2+(5t^4)^2} dt[/tex]
[tex]\rm L = \int^4_1\sqrt{25t^8+4t^2-8t+4} \;dt[/tex]
Now, simplify the above integration using the calculator.
L = 1023.0562
For more information, refer to the link given below:
https://brainly.com/question/18651211
