Answer:
The standard entalpy change for the reaction is 720 kJ/mol
Explanation:
The chemical equation for the reaction is given as follows;
TiO₂ (s) + 2C → Ti (s)  + 2CO
The standard enthalpy changes of formation for TiOâ‚‚ (s) = -940 kJ/mol
The standard enthalpy changes of formation for CO (g) = -110 kJ/mol
The enthalpy change of the reaction = The enthalpy of the products - The enthalpy of the reactants
Given that there are two moles of CO, we have;
The enthalpy of the products= -110 × 2 = -220 kJ/mol
∴ The enthalpy change = -220 - (-940) = 720 kJ/mol
The standard entalpy change for the reaction = 720 kJ/mol.